Hi, explain better, use mt4 to illustrate what you think and want.tradevn001 wrote: Sat Oct 26, 2019 4:24 am Hi everyone, I am in the process of learning how to coding. Could you help me with the code problem ount number of crossings of Moving Average.
Thank you very much!
Thanks for the reply. I want to code an indicator with the following content:pacois wrote: Sat Oct 26, 2019 6:20 am
Hi, explain better, use mt4 to illustrate what you think and want.
Try!!tradevn001 wrote: Sat Oct 26, 2019 12:48 pm
Thanks for the reply. I want to code an indicator with the following content:
For example, I use 3 MA10, 50 and 200 lines. When MA50 crosses MA200, count the number of cross of MA 10 with MA50.
Thank you very much!
Thanks so much for your help. Could you share the source of the indicator? I'm learning programming so I need to refer to the source code to better understand programming algorithms. Thank you very much.
Code: Select all
int start() {
int counted_bars=IndicatorCounted();
int i,limit;
int countup, countdown;
if(counted_bars<0) return(-1);
if(counted_bars>0) counted_bars--;
limit = MathMin(Bars-counted_bars,Bars-1);
countup = 0;
countdown = 0;
for(i=limit; i>=0; i--)
{
double ima1 = iMA(NULL,0,MA1,0,Ma_Methods,PRICE_CLOSE,i);
double ima2 = iMA(NULL,0,MA2,0,Ma_Methods,PRICE_CLOSE,i);
double ima11 = iMA(NULL,0,MA1,0,Ma_Methods,PRICE_CLOSE,i+1);
double ima21 = iMA(NULL,0,MA2,0,Ma_Methods,PRICE_CLOSE,i+1);
double ima3 = iMA(NULL,0,MA3,0,Ma_Methods,PRICE_CLOSE,i);
double ima4 = iMA(NULL,0,MA4,0,Ma_Methods,PRICE_CLOSE,i);
if (ima3 > ima4)
{
if ( ima1 > ima2 && ima11 < ima21)
{
countup ++;
countdown = 0;
}
}
if (ima3 < ima4)
{
if ( ima1 < ima2 && ima11 > ima21)
{
countup = 0;
countdown ++;
}
}
}
Comment (countup, countdown);
return(0);
}Hi, on 2000 Bar of 15 minutes only 3 crossings?
Yes, Only 3 crossing EMA 10 x EMA 50 when EMA 50 x EMA 200.