Code: Select all
B2[i]=(Close[i]-MathMin(Open[i+1],Close[i+1]))
B3[i]=(MathMax(Open[i+1],Close[i+1])-Close[i])
A fifth price has been added.
I was looking for an improvement with a microscope. Yes, it glues the gaps.
andrei-1, Sat Feb 18, 2023 3:26 pm
Code: Select all
B2[i]=(Close[i]-MathMin(Open[i+1],Close[i+1]))
B3[i]=(MathMax(Open[i+1],Close[i+1])-Close[i])